Find the value of tan20°15'.
(Refer the trigonometric table for the values)

0.3698

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0.3689

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0.3965

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0.3986

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Solution

The correct option is B 0.3689
We can write,
20°15' = 20° 12' + 3'
From the table we have, tan20°12' = 0.3679
Mean difference for, 3′ = 10

tan20°12' = 0.3679
+ 3′ = 10 (Mean difference to be added for tan)
____________________
tan20°15' = 0.3689

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