Find the value of the determinant ∣∣
∣∣bccaabpqr111∣∣
∣∣, where a, b and c are respectively the pth, qth and rth terms of a harmonic progression.
A
1
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B
pqr
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C
\N
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D
1abc
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Solution
The correct option is C \N Since, a, b, c are pth, qth and rth terms of HP. ⇒1a,1b,1c are in an AP. ⇒1a=A+(p−1)D1b=A+(q−1)D1c=A+(r−1)D⎫⎪
⎪
⎪⎬⎪
⎪
⎪⎭ . . . (i)
Let Δ=∣∣
∣∣bccaabpqr111∣∣
∣∣=abc∣∣
∣
∣∣1a1b1cpqr111∣∣
∣
∣∣ [from Eq. (i)] =abc∣∣
∣∣A+(p−1)DA+(q−1)DA+(r−1)Dpqr111∣∣
∣∣ApplyingR1→R1−(A−D)R3−DR2=abc∣∣
∣∣000pqr111∣∣
∣∣=0⇒∣∣
∣∣bccaabpqr111∣∣
∣∣=0