Find the value of the determinant 1-z 1-z -x-y-z2 -y-z-x2 1-x 1-x -yy-z-x2z x-2y-z-xy -yx-y-xz2

The correct option is D 0 nbsp;D=1/x^4z^4z amp; z amp; (x+y) nbsp; (y+z) amp; x amp; x nbsp; yz(y+z) amp; xz(x+2y+z) amp; ...

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Modulus of a Complex Number

Find the valu...

Question

Find the value of the determinant $∣ ∣ ∣ ∣ ∣ ∣ ∣ \begin{matrix} \frac{1}{z} & \frac{1}{z} & - \frac{(x + y)}{z^{2}} - \frac{(y + z)}{x^{2}} & \frac{1}{x} & \frac{1}{x} - \frac{y (y + z)}{x^{2} z} & \frac{x + 2 y + z}{x y} & - \frac{y (x + y)}{x z^{2}} \end{matrix} ∣ ∣ ∣ ∣ ∣ ∣ ∣$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ \begin{matrix} \frac{1}{z} & \frac{1}{z} & - \frac{(x + y)}{z^{2}} - \frac{(y + z)}{x^{2}} & \frac{1}{x} & \frac{1}{x} - \frac{y (y + z)}{x^{2} z} & \frac{x + 2 y + z}{x z} & - \frac{y (x + y)}{x z^{2}} \end{matrix} ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣

Δ = ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ \begin{matrix} \frac{1}{z} & \frac{1}{z} & \frac{- (x + y)}{z^{2}} \frac{- (y + z)}{x^{2}} & \frac{1}{x} & \frac{1}{x} \frac{- y (y + z)}{x^{2} z} & \frac{(x + 2 y + z)}{x z} & \frac{- (x + y)}{x z^{2}} \end{matrix} ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣

x, y, z

(x + y) (y + z) (z + x) (\frac{1}{x} + \frac{1}{y}) (\frac{1}{y} + \frac{1}{z}) (\frac{1}{z} + \frac{1}{x})

x + y + z = x y z

x (1 - y^{2}) (1 - z^{2}) + y (1 - z^{2}) (1 - x^{2}) + z (1 - x^{2}) (1 - y^{2})

x, y, z

(x + y) (y + z) (z + x) (\frac{1}{x} + \frac{1}{y}) (\frac{1}{y} + \frac{1}{z}) (\frac{1}{z} + \frac{1}{x})

Join BYJU'S Learning Program