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Byju's Answer
Standard XI
Mathematics
Basic Inverse Trigonometric Functions
Find the valu...
Question
Find the value of the expression
3
sec
−
1
(
2
)
−
6
sin
−
1
(
1
2
)
.
A
2
π
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B
5
π
6
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C
0
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D
1
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Solution
The correct option is
C
0
Since
,
sec
−
1
(
2
)
=
π
3
and
sin
−
1
1
2
=
π
6
∴
3
sec
−
1
(
2
)
−
6
sin
−
1
(
1
2
)
=
3
×
π
3
−
6
×
π
6
=
0
.
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0
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