Find the value of the expression (64x² + 81y² + 144xy), when x = 11 and $y = \frac{4}{3} .$

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Solution

$(64 x^{2} + 81 y^{2} + 144 x y) G i v e n : x = 11 y = \frac{4}{3} \Rightarrow {(8 x)}^{2} + {(9 y)}^{2} + 2 (8 x) (9 y) \Rightarrow {(8 x + 9 y)}^{2} \Rightarrow {(8 (11) + 9 (\frac{4}{3}))}^{2} \Rightarrow {(88 + 12)}^{2} \Rightarrow {(100)}^{2} \Rightarrow 10000$

Therefore, the value of the expression (64x² + 81y² + 144xy), when x = 11 and y = $\frac{4}{3}$ , is 10000.y=43

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Find the value of the expression

$(64 x^{2} + 81 y^{2} + 144 x y)$ when $x = 11$ and $y = \frac{4}{3}$

Q. Find the values of the following expressions:
(i) 16x² + 24x + 9, when

x = \frac{7}{4}

(ii) 64x² + 81y² + 144xy, when x = 11 and

y = \frac{4}{3}

(iii) 81x² + 16y² − 72xy, when

x = \frac{2}{3}

and

y = \frac{3}{4}

Find the values of the following expressions:

$(i) 16 x^{2} + 24 x + 9, w h e n x = \frac{7}{4} (i i) 64 x^{2} + 81 y^{2} + 144 x y, w h e n x = 11 a n d y = \frac{4}{3} (i i i) 81 x^{2} + 16 y^{2} - 72 x y, w h e n x = \frac{2}{3} a n d y = \frac{3}{4}$

Find $64 x^{2} + 81 y^{2} + \frac{144 x y}{48}$ when $x = 11$ and $y = \frac{4}{3}$

Q. Factorise :-

64 x^{2} - 81 y^{2}

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Find the value of the expression (64x2 + 81y2 + 144xy), when x = 11 and y=43.

64x2+81y2+144xyGiven: x=11 y =43⇒8x2 + 9y2 + 28x9y⇒8x +9y 2⇒8(11) +9(43)2⇒88 +122⇒1002⇒10000 Therefore, the value of the expression (64x2 + 81y2 + 144xy), when x = 11 and y = 43, is 10000.y=43

Find the value of the expression (64x² + 81y² + 144xy), when x = 11 and $y = \frac{4}{3} .$