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Question

Find the value of the expression at x=2 and y=1:
( 45) (39)+(21× x) (28× y) (152) 85+( 9)

A
550
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B
78
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C
66
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D
32
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Solution

The correct option is C 66
( 45) (39)+(21× x) (28× y) (152) 85+( 9)
( 45) (39)+(21× 2) (28× 1) (152) 85+( 9)
= 45 +39+42 28 +152 85 9
= 45 2885 9+39+42 +152
= 167+233
= 66

So, option (d) is correct.

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