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Question

Find the value of the expression:
(1+2x+3x2+4x3+.......)12, |x|<1.

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Solution

We have,
(1x)2=1+2x+3x2+4x3+...... [ When |x|<1]
Now,
(1+2x+3x2+4x3+.......)12
={(1x)2}12
=(1x)1
=1(1x)

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