Byju's Answer
Standard IX
Mathematics
Zeroes of a Polynomial
Find the valu...
Question
Find the value of the expression:
(
1
+
2
x
+
3
x
2
+
4
x
3
+
.
.
.
.
.
.
.
∞
)
1
2
,
|
x
|
<
1
.
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Solution
We have,
(
1
−
x
)
−
2
=
1
+
2
x
+
3
x
2
+
4
x
3
+
.
.
.
.
.
.
∞
[ When
|
x
|
<
1
]
Now,
(
1
+
2
x
+
3
x
2
+
4
x
3
+
.
.
.
.
.
.
.
∞
)
1
2
=
{
(
1
−
x
)
−
2
}
1
2
=
(
1
−
x
)
−
1
=
1
(
1
−
x
)
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