wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the value of the expression using BODMAS rule: 4x2÷x+(4×(2x3x2))32.

A
9x12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
9x4x2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
9x5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
4x5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 9x5
4x2÷x+(4×(2x3x2))32
We need to follow BODMAS rule.
=> Brackets (parts of a calculation inside brackets always come first).
=> Orders (numbers involving powers or square roots).
=> Division.
=> Multiplication.
=> Addition.
=> Subtraction.
= 4x2÷x+(4×(2x3x2))32
= 4x+(4×2x)9
= 4x8x9
= 9x5

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon