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Question

Find the value of the following:-
(a) sin312cos59
(b) sec702cosec20+sin59cos31

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Solution

a.sin31°2cos59°=sin31°2cos(90°31°)=sin31°2sin31°
=12
b. sec70°2csc20°+sin59°cos31°
sec70°2csc(90°70°)+sin59°cos(90°59°)
=sec70°2sec70°+sin59°sin59°
=12+1=32

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