Question

Find the value of the following determinant:

$\left|\begin{array}{cc}3\sqrt{6}& -4\sqrt{2}\\ 5\sqrt{3}& 2\end{array}\right|$

• A. $20\sqrt{6}$
• B. $16\sqrt{6}$
• C. $26\sqrt{6}$
• D. $10\sqrt{6}$

Answer 1

The correct option is C $26\sqrt{6}$

The value of the determinant $\left|\begin{array}{cc}3\sqrt{6}& -4\sqrt{2}\\ 5\sqrt{3}& 2\end{array}\right|$ is

$(2\times 3\sqrt{6})-(5\sqrt{3}\times (-4\sqrt{2}\left)\right)$

$=6\sqrt{6}-(-20\sqrt{6})=6\sqrt{6}+20\sqrt{6}$

$=26\sqrt{6}$