Question

Find the value of the following determinant:

$\left|\begin{array}{cc}\frac{-4}{7}& \frac{-6}{35}\\ 5& \frac{-2}{5}\end{array}\right|$

• A. $\frac{15}{34}$
• B. $\frac{32}{45}$
• C. $\frac{25}{33}$
• D. $\frac{38}{35}$

Answer 1

The correct option is D $\frac{38}{35}$

The value of $\left|\begin{array}{cc}\frac{-4}{7}& \frac{-6}{35}\\ 5& \frac{-2}{5}\end{array}\right|$ is

$(\frac{-4}{7}\times \frac{-2}{5})-(\frac{-6}{35}\times 5)$

$=\frac{8}{35}+\frac{30}{35}$

$=\frac{38}{35}$