Find the value of the following equation, when the value of m = 150.
m×(1−12)×(1−13)×(1−14)×(1−15)×(1−16)…………(1−1m)=?
149
1
150
(1/149)
None of these
[12×23×34×45×…………×149150]×150=1
If x=23 is a solution of the quadratic equation 7x2+mx−3=0, find the value of m.
Solve the following equations
(1) (x + 4) (x − 4) = 6x
(2) 2(a2 − 1) = a(1 − a)
(3) 3(b − 5) (b − 7) = 4 (b + 3)
(4) 8(s − 1) (s + 1) + 2(s + 3) = 1
(5) (n − 3)2 + (n + 1)2 = 16
(6) 11(m + 1) (m + 2) = 38(m + 1) + 9m