Find the value of the following expression, when $x = - 1$ .
$2 x^{2} - x - 2$ .

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Solution

$x = - 1$
$2 x^{2} - x - 1$
$2 {(- 1)}^{2} - (- 1) - 2 = 2 - 2 + 1$
$= 1$

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Question 3 (iv)

Find the value of the following expressions, when x = -1:
$2 x^{2} - x - 2$

\frac{1 - x^{2}}{2 x^{3} - 1} \div \frac{1 - x}{2 x^{2}}

(1)

x = \infty

(2)

x = 0

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