Find the value of the following expressions, when $x = - 1$ :
$x^{2} + 2 x + 1$

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Solution

$x = - 1 (Given)$

Therefore,

$x^{2} + 2 x + 1$

$= {(- 1)}^{2} + 2 \cdot (- 1) + 1$

$= 1 - 2 + 1$

$= 0$

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x = - 1

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Find the value of the following expression, when x = -1:
$x^{2} + 2 x + 1$

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