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Question

Find the value of the following.
(i) sin50°cos40° + cosec40°sec50° - 4cos 50°. cosec 40°

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Solution

sin 50°cos 40°+cosec 40°sec 50°-4cos 50°.cosec 40°= sin (90-40)°cos 40°+cosec (90-50)°sec 50°-4cos (90-40)°cosec 40°= cos 40°cos 40°+ sec 50°sec 50°-4sin 40°cosec 40° cosec90-θ=sec θ & sin90-θ=cos θ= 1+1-4= -2

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