Question

Find the value of the following: ${\left(3\right)}^0+{\left(4\right)}^0+{\left(9\right)}^0+{\left(16\right)}^0$

Answer 1

As we know the law of exponential ,

${\left(x\right)}^0=1$

Given exponential form, ${\left(3\right)}^0+{\left(4\right)}^0+{\left(9\right)}^0+{\left(16\right)}^0$

Using the above law of exponential:

$$\begin{gathered} \Rightarrow {\left(3\right)}^0+{\left(4\right)}^0+{\left(9\right)}^0+{\left(16\right)}^0=1+1+1+1 \\ =4 \end{gathered}$$

Hence, the required value is $4$.