Question

Find the value of the following: ${\left[{(-7)}^0\right]}^8+{(-1)}^{60}$

Answer 1

Hint: The law of exponential is:

$x^0=1$

Step 1: Given exponential form: ${\left[{(-7)}^0\right]}^8+{(-1)}^{60}$

Step2: Solution:

Using the above law of exponential:

$$\begin{gathered} {\left[{(-7)}^0\right]}^8+{(-1)}^{60}={\left(1\right)}^8+{(-1)}^{60}\{U\sin g{x}^0=1\} \\ =1+1 \\ =2 \end{gathered}$$

$2$, This is the required value.

Final Answer: $2$, This is the required value.