Find the value of the following logarithms:
(A) ${log}_{2} 8$
(B) ${log}_{12} 1$

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Solution

(A) ${log}_{2} 8 = {log}_{2} 2^{3} = 3 {log}_{2} 2 = 3$
(B) ${log}_{12} 1 = 0$

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Similar questions

log 2 = 0.3010

log 3 = 0.4771

log 12

log 2 = 0.3010

log 3 = 0.4771

log 12

1.0791

\frac{l o g 144}{l o g 12}

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$(i) l o g 12 = l o g 3 + l o g 4$

$(i i) l o g 50 = l o g 2 + 2 l o g 5$

$(i i i) l o g (1 + 2 + 3) = l o g 1 + l o g 2 + l o g 3$

3 l o g 2 - \frac{1}{3} l o g 27 + l o g 12 - l o g 4 + 3 l o g 5

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