Find the value of the following.
$sin 0^{o} + cos 30^{o} - tan 45^{o} + c o s e c 60^{o}$ .

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Solution

We have,
$sin 0^{o} + cos 30^{o} - tan 45^{o} + c o s e c 60^{o}$
$= 0 + \frac{\sqrt{3}}{2} - 1 + \frac{2}{\sqrt{3}}$
$= \frac{3 - 2 \sqrt{3} + 4}{2 \sqrt{3}}$
$= \frac{7 - 2 \sqrt{3}}{2 \sqrt{3}}$

Hence, this is the answer.

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