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Question

Find the value of the following, using suitable properties:

a) 406×516

b) 8 ×291×125
[3 MARKS]

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Solution

Steps: 1×2=2 Marks
Answer: 0.5×2=1 Mark

a) By distributive law

406×516 = (400 + 6)×(500 + 16)
= 200000 + 96 + 6400 + 3000 = 2,09,496

b) By distributive law
8 ×291×125=(4×2)×(290+1)×(25× 5)=(25× 4)×(5×2)×(290+1)
= 100 × 10 × (290+1) = 1000 × (290+1)
= 290000 + 1000 = 291000


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