Question

Find the value of the given expression
$(x^3+2x^2+3x)÷2x$

• A. 1/2(x²+2x+3)
• B. 1/2
• C. (x²+2x+3)
• D. 1

Answer 1

The correct option is A

1/2(x²+2x+3)

Divide all the terms of the expression $(x^3+2x^2+3x)$ separately by $2x$.
$\frac{x^3}{2x}=\frac{x^2}{2}$;
$\frac{2x^2}{2x}=x$;
$\frac{3x}{2x}=\frac{3}{2}$.
Therefore, $\frac{(x^3+2x^2+3x)}{2x}=\frac{x^2}{2}+x+\frac{3}{2}=\frac{(x^2+2x+3)}{2}$