We have, A B× 6________C 6 8
Here, 6×B is a number, whose unit's whose digit is 8. Therefore, the possible values of B are 3 and 8.
The possible values of B×6 are 18 and 48 respectively
If B = 3, then A ×6 + 1 = C6.
A×6 = C5, As any value of A doesnt give 5 as unit's digit when multiplied with 6, this assumpition is wrong.
So, the possible value of B is 8
∴ B = 8 and then A = 7.
If A = 7, then (7×6)+4=C646=C6∴C=4
Hence, A = 7, B = 8 and C = 4