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Question

Find the value of the limit: limx0sin1xsinxx3

A
12
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B
13
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C
14
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D
15
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Solution

The correct option is D 13
limx0sin1xsinxx3=00 Form.

By L-Hospital Rule

limx01x2+1cosx3x2=00 Form.

limx0x(1x2)3/2+sinx6x=00 Form.

again L-Hospital.

limx0(1x2)3/2+x.32(1x2)1/2.2x+cosx6=26

=13

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