Find the value of the polynomial $4x^2-5x+3$, when $x=\frac{1}{2}$

The correct option is A.$\frac{3}{2}$

Given polynomial is $p\left(x\right)=4x^2-5x+3$

We need to find value of $x=\frac{1}{2}$.

Substituting the value of $x$ as $x=\frac{1}{2}$, we get,

$p\left(\frac{1}{2}\right)=4{\left(\frac{1}{2}\right)}^2-5\left(\frac{1}{2}\right)+3$

$\Rightarrow p\left(\frac{1}{2}\right)=4\times \frac{1}{4}-5\times \frac{1}{2}+3$

$\Rightarrow p\left(\frac{1}{2}\right)=1-\frac{5}{2}+3=\frac{2-5+6}{2}=\frac{3}{2}$ [Taking $2$ as LCM]

Hence, at $x=\frac{1}{2}$, $4x^2-5x+3=\frac{3}{2}$