Find the value of the polynomial $5 x - 4 x^{2} + 3$ at $x = - 1, 2, - 2$

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Solution

Value of polynomial $5 x - 4 x^{2} + 3$ $&$ $x = 0, - 1, 2, - 2$

$\Rightarrow p (x) = 5 x - 4 x^{2} + 3$

$p (- 1) = 5 (- 1) - 4 {(- 1)}^{2} + 3 = - 5 - 4 + 3 = - 6$

$p (- 2) = 5 (2) - 4 {(2)}^{2} + 3 = 10 - 16 + 3 = - 3$

$p (- 3) = 5 (- 2) - 4 {(- 2)}^{2} + 3 = - 10 - 16 + 3 = - 23$
Hence, solve.

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Find the value of the polynomial $5 x - 4 x^{2} + 3$ at
(i) $x = 0$
(ii) $x = - 1$
(iii) $x = 2$

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