Find the value of the polynomial $5 x - 4 x^{2} + 3$ at
(i) x = 0
(ii) x = - 1
(iii) x = 2

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Solution

$p (x) = 5 x - 4 x^{2} + 3$
(i) $A t x = 0, p (0) = 5 \times 0 - 4 \times 0^{2} + 3 = 3$
(ii) At x = - 1, p(-1) = $5 \times (- 1) - 4 \times (- 1)^{2} + 3 = - 5 - 4 + 3 = - 6$
(iii) At x = 2, p(2) = $5 \times 2 - 4 \times (2)^{2} + 3 = 10 - 16 + 3 = - 3$

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Similar questions

Find the value of the polynomial $5 x - 4 x^{2} + 3$ at
(i) $x = 0$
(ii) $x = - 1$
(iii) $x = 2$

5 x - 4 x^{2} + 3

5 x - 4 x^{2} + 3

x = 2

4 x^{2} - 5 x + 3

x = \frac{1}{2}

5 x - 4 x^{2} + 3

x = - 1

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