Find the value of the polynomial $x^{2} + 2 x + 5$ when, $x = - 1$

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $4$
Let $f (x) = x^{2} + 2 x + 5$
When $x = - 1$ ,
$f (- 1) = (- 1)^{2} + 2 (- 1) + 5$
$= 1 - 2 + 5$
$= 4$

Suggest Corrections

Similar questions

x^{2} + 2 x + 5

x = - 3

x^{2} + 2 x + 5

x = 0

Statement 1: The value of the polynomial ${x}^{5}+ 2{x}^{4}+ 3{x}^{3}+ {x}^{2}– 7x + 8$ at x = -1 is 14.

Statement 2: The polynomial ${x}^{5}+ 2{x}^{4}+ 3{x}^{3}+ {x}^{2}– 7x + 8$ when divided by x + 1, gives 14 as remainder.

The value of the polynomial $5 x - 4 x^{2} + 3$ , when $x = - 1$ is
A) $- 6$
B) $6$
C) $2$
D) $- 2$

P (x) = x^{2} - 2 x + 5

x = - 1

x = 5

Join BYJU'S Learning Program