Question

Find the value of the trigonometric function $\sin {765}^{\circ }$.

Answer 1

It is known that the values of sin⁡𝑥 repeat after an interval of $2\pi$ or ${360}^{\circ }$
$\therefore \sin {765}^{\circ }=\sin \left(2\right({360}^{\circ })+{45}^{\circ })$
$=\sin {45}^{\circ }$
$=\frac{1}{\sqrt{2}}$