Find the value of the trigonometric functions in tan $\frac{19 π}{3}$ .

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Solution

tan $\frac{19 π}{3} = t a n \frac{19}{3} \times 180$

= tan $1140^{0}$

tan $1140^{0}$ = tan $(3 \times 360^{0} + 60^{0})$

= tan $60^{0} = \sqrt{3}$

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