Question

Find the value of the unknown $x$ in the following diagrams.

Answer 1

We know that,

The sum of the angles in a triangle is ${180}^0$

In figure (1),

$x+{50}^0+{60}^0={180}^0$

$x={180}^0-{110}^0$

$x={70}^{0}Ans.$

In figure (2),

$x+{90}^0+{30}^0={180}^0$

$x={180}^0-{120}^0$

$x={60}^{0}Ans.$

In figure (3),

$x+{30}^0+{110}^0={180}^0$

$x={180}^0-{140}^0$

$x={40}^{0}Ans.$

In figure (4),

$x+x+{50}^0={180}^0$

$2x={180}^0-{50}^0$

$2x={130}^0$

$x={65}^{0}Ans.$

In figure (5),

$x+x+x={180}^0$

$3x={180}^0$

$x={60}^{0}Ans.$

In figure (6),

$x+2x+{90}^0={180}^0$

$3x={180}^0-{90}^0$

$3x={90}^0$

$x={30}^{0}Ans.$

hence, this is the answer.