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Question

Find the value of θ in each of the following

(1) 2 sin 2θ = 3

(2) 2 cos 3θ = 1

(3) 3tan 2θ - 3 = 0

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Solution

(1) we have,
2sin 2θ = 3
sin 2θ = 32
sin 2θ = sin 260
θ = 30

(2) we have, 2cos 3θ = 1
cos3θ = 12
coss 3θ = cos 60
3θ = 60
θ= 20

(3) we have, 3tan 2θ - 3 = 0 \
3tan 2θ = 3
tan 2θ = 33 = 3
tan 2θ = tan 60 2θ = 60 θ = 30


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