Question

Find the value of $\theta$ in each of the following :
$\sqrt{3}tan2\theta -3=0$

Answer 1

We have,
$\sqrt{3}tan2\theta$ - 3 = 0

$\sqrt{3}tan2\theta$ = 3

$\Rightarrow tan2\theta =\frac{3}{\sqrt{3}}=\sqrt{3}\Rightarrow tan2\theta =tan{60}^{\circ }\Rightarrow 2\theta ={60}^{\circ }\Rightarrow \theta ={30}^{\circ }$