Question

Find the value of x.

$1)\left(\frac{x}{3}\right)+\left(\frac{1}{4}\right)=\left(\frac{x}{2}\right)-\left(\frac{2}{5}\right)$

$2\left)0.25\right(3x-1)=0.05(8x-6)$ [4 MARKS]

Answer 1

Concept: 1 Mark each
Application: 1 Mark each

$1)\left(\frac{x}{3}\right)+\left(\frac{1}{4}\right)=\left(\frac{x}{2}\right)-\left(\frac{2}{5}\right)$

$\left(\frac{x}{3}\right)-\left(\frac{x}{2}\right)=-\frac{2}{5}-\frac{1}{4}$

$\frac{x}{6}=\frac{13}{20}$

$x=\frac{39}{10}=3.9$


$2\left)0.25\right(3x-1)=0.05(8x-6)$

$\frac{3x-1}{4}=\frac{8x-6}{20}$

By cross multiplication

$15x–5=8x–6$

$7x=-1$

$x=\frac{-1}{7}$