Find the value of x.
120o
60o
75o
90o
Given : The lines are parallel.
∠ OO'Q = ∠ PO'Y (vertically opposite angles)
⇒ ∠ OO'Q = 120∘
∠ OO'Q + x = 180∘ (Co-interior angles)
⇒120∘+x=180∘
⇒ x = 60∘