Find the value of $x$ .
$2 l o g_{e} x = tan 45^{0}$

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Solution

$\begin{matrix} 2 {log}_{e} x = tan 45^{0} \Rightarrow 2 {log}_{e} x = 1 \Rightarrow {log}_{e} x = \frac{1}{2} ∴ x = e^{\frac{1}{2}} \end{matrix}$

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