Find the value of $x$
$2 x^{3} + 24 x^{2} + 72 x$

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Solution

$2 x^{3} + 24 x^{2} + 72 x = 0$
$2 x (x^{2} + 12 x + 36) = 0$
$x (x^{2} + 6 x + 6 x + 36) = 0$
$x (x + (x + 6) + 6 (x + 6)) = 0$
$x (x + 6) (x + 6) = 0$
$x {(x + 6)}^{2} = 0$
Roots $⟶ x = 0, - 6$

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