Find the value of x3+27y3+9x2y+27xy2 when x=55 and y=15.
1000000
The given expression is similiar to the expansion of the identity (a+b)3, i.e.,
x3+27y3+9x2y+27xy2=x3+(3y)3+3×x2×3y+3×x×(3y)2=(x+3y)3
Substituting the values of x and y in (x+3y)3
⇒(x+3y)3=(55+3×15)3=1003=1000000