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Question

Find the value of x3+x2+2x+4 when x=1+3i.

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Solution

We know that, i2=1i3=i

x3+x2+2x+4=(1+3i)3+(1+3i)2+2(1+3i)+4=(1+33i3+33i+3.3.i2)+(1+3i2+23i)+2(1+3i)+4=133i+33i9+13+23i+2+23i+4=19+13+2+4+43i=0+43i=43i

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