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Question

Find the value of x3x2+x+46 if x=2+3i

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Solution

Given that,

x=2+3i

x2=(2+3i)=4+9i+12i

x2=5+12i

x3=10+24i15i+36i2

x3=46+9i

x3x2+x+46

46+9i+512i+2+3i+46

7

x3x2+x+46=7


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