Find the value of $x$ :-
$4 x^{2} - 9 x = 0$

4, \frac{9}{4}

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0, \frac{5}{4}

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0, \frac{9}{4}

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None of these

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Solution

The correct option is C $0, \frac{9}{4}$
value of $x$ in $4 x^{2} - 9 x = 0$

taking $x$ common $x (4 - 9 x) = 0$

$x = 0$ OR $4 - 9 x = 0$

$4 = 9 x$

$x = \frac{9}{4}$
two values of $x$ are $0$ , $\frac{9}{4}$

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Similar questions

x^{4} + 9 x^{4} + 35 x^{4} + 4

x = - 5 + 2 \sqrt{- 4}

If $x \neq 0$ and $x + \frac{1}{2 x}$ = 4, then find the value of $x^{2} + \frac{1}{4 x^{2}}$

(\frac{4}{9})^{x} \times (\frac{4}{9})^{- 7} = (\frac{4}{9})^{2 x + 1} .

x = - 5 + 2 \sqrt{- 4}

x^{4} + 9 x^{3} + 35^{2} - x + 4

x = - 5 + 2 \sqrt{- 4},

x^{4} + 9 x^{3} + 35 x^{2} - x + 4

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