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Question

Find the value of x4x3+x2+3x5 if x = 2+3i

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Solution

x4x3+x2+3x5

(2+3i)4(2+3i)3+(2+3i)2+3(2+3i)5

(2+3i)4:119120i

(2+3i)3:46+9i

(2+3i)2:5+12i

=(119120i)+469i+(5+12i)+6+9i5

=119120i+469i5+12i+6+9i5

=120i9i+12i+9i119+465+65

=108i119+465+65

=77108i

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