FIND THE VALUE OF x: a) IF sin2x = sin60°cos30°- cos60°sin30° b) IF cos(40°+x)= sin30°
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Solution
Sin(A-B)=sin A cos B-cos A sin B here sin2X=sin 60 cos 30-cos 60 sin 30 comparing this 2 equations we get 2X=(60-30)=30 X=15 2.WE know sin 30=cos(90-30)=cos 60 so here cos(40+x)=sin 30 comparing this we get 40+x=60 x=20 like if you r satisfied