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B
7
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C
2
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Solution
In the given line segment, both end points have the same ordinates. ∴ The ordinate of C is also 2. ⇒x=2
From the given figure, AB = AC ⇒AB2=AC2⇒(2−1)2+(0−3)2=(2−(−1))2+(0−x)2 ⇒x=±1
The diagonals of parallelogram bisect each other.
So, the coordinates of the midpoint of AC = coordinates of the midpoint of BD.
ie.,(6+92,1+42)=(8+x2,2+32) ⟹(152,52)=(8+x2,52) ⟹152=8+x2 ⟹x=7