Find the value of x and y from the pair of linear equations, using cross-multiplication method.

$\frac{1}{5}$ (x – 2) = $\frac{1}{4}$ (1 – y)

26x + 3y + 4 = 0

x = 2, y = 1/3

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x = -2, y = 1/3

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x = -1/2, y = 3

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x = 2, y = 3

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Solution

The correct option is C
x = -1/2, y = 3

$\frac{1}{5 (x - 2)}$ = $\frac{1}{4 (1 - y)}$

4 (x – 2) = 5 (1 – y)

4x – 8 – 5 + 5y = 0

4x + 5y – 13 = 0 ------ (1)

26x + 3y + 4 = 0 ------ (2)

Using cross multiplication method

$\frac{x}{20 + 39}$ = $\frac{y}{(- 13) (26) - 16}$ = $\frac{1}{12 - 130}$

x = $\frac{59}{- 118}$ = - $\frac{1}{2}$

y = $\frac{- 354}{- 118}$ = 3

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Find the value of x and y from the pair of linear equations, using cross-multiplication method. 15 (x – 2) = 14(1 – y) 26x + 3y + 4 = 0

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Find the value of x and y from the pair of linear equations, using cross-multiplication method.

$\frac{1}{5}$ (x – 2) = $\frac{1}{4}$ (1 – y)

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