Find the value of x and y, if [x+yy2xx−y][2−1]=[32]
[2(x+y)−y4x−(x−y)]=[32]
[2x+y3x+y]=[32]
Comparing the two matrices, we get
2x + y = 3
3x +y = 2
On solving, we get x = -1 and y = 5
Find x and y, if [2xxy3y][32]=[169]