Question

Find the value of $x$ and $y$ in the adjoining figure.

Answer 1

Ref . Image .

$\Delta$ ABC $\cong \Delta$ PQR by sss property

so Angle $\angle$ ACB = $\angle$ RQP

${40}^{\circ }=y$

$y={40}^{\circ }$

$\angle$ ABC ${60}^{\circ }$

$\angle x+\angle ABC+\angle ACB={180}^{\circ }$

$\angle x=180-(60+40)$

$\angle x={80}^{\circ }$

$x={80}^{\circ }$