Find the value of x and y respectively-83 - 73 - 1 - x - y - 3

A^3 – b^3 = (a b)^3 + 3ab(a b) 8^3 7^3 = (8 7)^3 + 3 × 8 × 7 × (8 7) — (i) 8^3 7^3 = 1 + x × y × 3 — (ii) Comparing (i) and (ii), we get; x = 8 an ...

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Standard VIII

Mathematics

Cube Numbers

Find the valu...

Question

Find the value of x and y respectively.
$8^{3}$ - $7^{3}$ = 1 + x $\times$ y $\times$ 3

8,7

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8,6

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7, 9

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6,8

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Solution

The correct option is A
8,7

$a^{3}$ – $b^{3}$ = $(a - b)^{3}$ + 3ab(a - b)
$8^{3}$ - $7^{3}$ = $(8 - 7)^{3}$ + 3 $\times$ 8 $\times$ 7 $\times$ (8 - 7) ---- (i)
$8^{3}$ - $7^{3}$ = 1 + x $\times$ y $\times$ 3 ----(ii)
Comparing (i) and (ii), we get;
x = 8 and y = 7

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Find the value of x and y respectively. 83 - 73 = 1 + x × y ×​ 3

The correct option is A 8,7 a3 – b3 = (a−b)3 + 3ab(a - b)​ ​83 - 73 = (8−7)3 + 3 × 8 × 7 × (8 - 7) ---- (i) 83 - 73 = 1 + x × y ×​ 3 ----(ii) Comparing (i) and (ii), we get; x = 8 and y = 7

Find the value of x and y respectively.
$8^{3}$ - $7^{3}$ = 1 + x $\times$ y $\times$ 3

The correct option is A
8,7

$a^{3}$ – $b^{3}$ = $(a - b)^{3}$ + 3ab(a - b)
$8^{3}$ - $7^{3}$ = $(8 - 7)^{3}$ + 3 $\times$ 8 $\times$ 7 $\times$ (8 - 7) ---- (i)
$8^{3}$ - $7^{3}$ = 1 + x $\times$ y $\times$ 3 ----(ii)
Comparing (i) and (ii), we get;
x = 8 and y = 7