The correct option is C (1, -1)
2x−y=3 ----- (1)
4x+y=3 ----- (2)
First use formula for cross multiplication method:
xb1c2−b2c1=yc1a2−a1c2=−1a2b2−a2b1
So, from equation (1) and (2) we can write the value of a, b and c.
x(−1)×3−(1)×3=y3×4−2×3=−12×(1)−4×(−1)
x−3−3=y12−6=−12+4
x−6=y6=−16
x−6=−16
x=66=1
y6=−16
y=−66
y=−1
The solution is (1, -1)