The correct option is B (4,3)
6x−5y=9 ----- (1)
5x−6y=2 ----- (2)
First use formula for cross multiplication method:
xb1c2−b2c1=yc1a2−a1c2=−1a2b2−a2b1
So, from equation (1) and (2) we can write the value of a, b and c.
x(−5)×2−(−6)×9=y9×5−6×2=−16×(−6)−5×(−5)
x−10+54=y45−12=−1−36+25
x44=y33=−1−11
x44=−1−11
x=−44−11=−3
y33=−1−11
y=−33−11
y=3
The solution is (4,3)